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A sample of gas in a balloon has an initial temperature of 42 ∘C and a volume of 1.10×103 L . If the temperature changes to 86 ∘C , and there is no change of pressure or amount of gas, what is the new volume, V2, of the gas?

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Respuesta :

Answer:

1250L or 1.25*10^3

Explanation:

Use the combined gas law, [tex]\frac{P_{1} V_{1}}{T_{1} }[/tex]=[tex]\frac{P_{2}V_{2}}{T_{2} }[/tex]

Put the value for the temperature(in Kelvin) and volume, and you can just put 1 for P1 and P2 because it stays the same.

I'll assume that you meant to put 1.10*10^3L