You throw a ball into the air from a height of 5 feet with an
initial vertical velocity of 32 feet per second. Use the vertical
motion model, h = –16t2 + vt + s, where v is the initial
velocity in feet per second and s is the height in feet, to
calculate the maximum height of the ball. Round your answer
to the nearest tenth if necessary.
Maximum height

Relax

Respuesta :

Answer: 21 ft

X = -32/2(-16) = 1 = time

-16(1)^2 + 32(1) + 5 = 21 ft!