Answer:
The component form of the vector P'P is [tex]\left \langle -7, 2 \right \rangle[/tex]
Step-by-step explanation:
The component form of the vector that translates P(4, 5) to P'(-3, 7), is given as follows;
The x-component of the vector = The difference in the x-values of the point P' and the point P = -3 - 4 = -7
The y-component of the vector = The difference in the y-values of the point P' and the point P = 7 - 5 = 2
The component form of the vector P'P = [tex]\left \langle -7, 2 \right \rangle[/tex]
