The half-life of Palladium-100 is 4 days. After 20 days a sample of Palladium-100 has been reduced to a
mass of 5 mg.
What was the initial mass (in mg) of the sample?
What is the mass (in mg) 4 weeks after the start?
You may enter the exact value or round to 4 decimal places

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TimMil

Answer:

A = (Ao)(0.5^(t/t1.2))

1 = (Ao)(0.5^(20/4)) = Ao(0.03125)

Ao = 1/0.03125 = 32mg

5 weeks = 5(7) = 35 days

A = 32(0.5^(35/4)) = 32(0.0232) = 0.074mg

Step-by-step explanation: