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A 60.0 g sample of chromium at 82.0°C (specific heat for chromium is 0.11 J/g°C) was placed in 80.0 g of water. Assume there is no loss of heat to the environment. What is the temperature of the water and the chromium? The water's initial temperature was 24.0°C.

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ardni313

The temperature of the water and the chromium : 25.122 ° C  

Further explanation  

The law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released  

Q in(gained) = Q out (lost)

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

Q Chromium= Q water

[tex]\tt 60\times 0.11\times (82-t)=80\times 4.18\times (t-24)\\\\541.2-6.6t=334.4t-8025.6\\\\341t=8566.8\\\\t=25.122^oC[/tex]

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