A rock is thrown from the top of a ladder. The function
h(t) = –16t2 + 120t + 10 gives the height of the rock t seconds after it is
thrown a certain number of feet.
What is the height of the rock at 5 seconds?

Respuesta :

Answer:

h'(t)=88

Step-by-step explanation:

h'(t)=d/dt (-16t x 2 + 120t + 10

h'(t)=d/dt (-32t + 120t + 10)

h'(t)=d/dt (88t + 10)

h'(t)=d/dt (88t) + d/dt (10)

h'(t)=88 + 0