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14-11-2020
Mathematics

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12x + 7 < -11 AND 5x – 8 > 40

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zihlavsk zihlavsk

14-11-2020

Answer:

[tex]x<1\frac{1}{2}[/tex] and [tex]x> 9\frac{3}{5}[/tex]

Step-by-step explanation:

12x+7<-11 subtract 7 from both sides 12x<-18 divide both sides by 12 x<1.5

5x-8>40 add 8 to both sides 5x>48 divide both sides by 5 x>9.6

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