Respuesta :
Answer:
The acceleration of the block is 1.21 m/sยฒ.
Explanation:
Given that,
Mass = 2.0 kg
Force = 25.0 n
Angle = 30ยฐ
Coefficient of friction = 0.752
We need to calculate the acceleration of the block
Using balance equation
[tex]F-(mg\sin\theta+\mu mg\cos\theta)=ma[/tex]
Put the value into the formula
[tex]25-(2.0\times9.8\sin30+0.752\times2.0\times9.8\cos30)=2.0a[/tex]
[tex]a=\dfrac{25-(2.0\times9.8\sin30+0.752\times2.0\times9.8\cos30)}{2.0}[/tex]
[tex]a=1.21\ m/s^{2}[/tex]
Hence, The acceleration of the block is 1.21 m/sยฒ.
