
Answer:
P (A|C) = 0.39
P (C|A) = 0.446
Step-by-step explanation:
The data provided is as follows:
                       Blood Group
                 O      A       B      AB     Total
             1)   0.082   0.101   0.005   0.004   0.192
Ethnic Group  2)   0.140   0.141    0.018   0.009   0.578
            3)   0.215   0.195   0.070   0.020   0.500
   Total         0.437   0.437   0.093   0.033
The event C = {Ethnic group 3 is selected}
Compute the value of P (A|C) as follows:
[tex]P(A|C)=\frac{P(A\cap C)}{P(C)}=\frac{0.195}{0.5}=0.39[/tex]
If we know that the individual came from ethnic group 3, the probability that he has type A is given by P(A | C) = 0.39.
Compute the value of P (C|A) as follows:
[tex]P(C|A)=\frac{P(A\cap C)}{P(A)}=\frac{0.195}{0.437}=0.446[/tex]
If we know that the individual has type A blood group, the probability that he came from ethnic group 3 is given by P(C | A) = 0.446.