Answer:
The value is [tex]a = -5.625 \ m/s^2[/tex]
Explanation:
From the question we are told that
The speed of the driver is [tex]u = 30.0 \ m/s[/tex]
The distance of the car from the moose is [tex]s= 80 \ m[/tex]
Generally from the third equation of motion we have that
[tex]v ^2 = u ^2 + 2as[/tex]
Here  v =  0 \  m/s
So
   [tex]0  =  30 ^2  +  2 * a * 80[/tex]
    [tex]a =  -5.625 \ m/s^2[/tex]
