barronomar777 barronomar777
  • 14-09-2016
  • Mathematics
contestada

2x^{2} +4x+1=0
Solve for x.

Relax

Respuesta :

mpanderla95
mpanderla95 mpanderla95
  • 14-09-2016
2x^2 + 4x + 1 = 0

2x^2 + 4x + 1 - 1 = 0 - 1

2x^2 + 4x = -1

X(2x + 4) = -1

X = -1.

2x + 4 = -1
2x + 4 - 4 = -1 - 4
2x = -5
2x/2 = -5/2
X = -5/2.

I believe these are the solutions. If not you can use the quadratic formula to solve for the roots, solutions.
Answer Link

Otras preguntas

what mass of water forms when 2.75 x 10-4 mol NaOH reacts completely
Fiona and her fellow Green Committee members are working on a proposal for improving recycling at school. What might they do to identify ways to increase studen
Simplify the expressions. show your work. 3x(4x4 – 5x)
Write -2x 2(-5x 2 4x 3) in standard form. a. -8x5 - 20x4 b. -8x5 10x4 c. -7x 2x4 d. -7x5 - 10x4
find a cubic function with the given zeros. square root of seven., -square root of seven., -4
Goods that are considered to be needs tend to be
PLEASE HELP? What is the measure of ED in circle H? 130° 90° 50° 180°
The fifth term of an arithmetic sequence is 9 and the 32nd term is -84. What is the 23rd term?
Who was the leader of the soviet union during world war 2?
A solution is considered acidic if its ph is _________ 7. a. equal to b. less than c. greater than