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The free-fall acceleration at the surface of planet 1 is 15 m/s2. The radius and the mass of planet 2 are twice those of planet 1. Part A What is g on planet 2

Relax

Respuesta :

Sriju

Answer:

3.75m/s²

Explanation:

g= GM/r²

For planet 1

[tex]g_{1}[/tex]= GM/r²                   (i)

[tex]g_{1}[/tex] = 15m/s²

for planet 2

radius= 2*r= 2r

g= GM/r

[tex]g_{2}[/tex]= GM/(2r)²

[tex]g_{2}[/tex]= GM/4r²

[tex]g_{2}[/tex]=  GM/r² *1/4

from (i)

[tex]g_{2}[/tex]=  [tex]g_{1}[/tex] *1/4

[tex]g_{2}[/tex] = 15/4

[tex]g_{2}[/tex] = 3.75m/s²

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