Answer:
Hey there!
For question 1:
C(11,5) = (11!)/(5!*(11-5)!)
C(11,5) = (11!)/(5!*6!)
C(11,5) = (11*10*9*8*7*6!)/(5!*6!)
C(11,5) = (55440)/(120)
C(11,5) = 462 ways
For question 2:
10!=10*9*8*7*...*2*1= 3628800 ways.
This can be a challenging and confusing topic, so let me know if you want a easier to understand explanation, I'm always here to give one :)
A number of ways to choose the players are 462 and The coach made a batting order is 3,268,800.
A permutation is an act of arranging the objects or elements in order.
1. Β Rylan's basketball team has 11 players.
His coach chooses five starting players.
The number of different ways to choose the players.
[tex]\rm ^{11}C_{5} = \dfrac{11!}{5! (11-5)!} = 462[/tex]
2. Β Sarah plays softball over the summer. If there are 10 players on the team.
The coach made a batting order that will be
[tex]10! = 10*9*8*7*6*5*4*3*2*1 = 3268800[/tex]
Thus, A number of ways to choose the players are 462 and The coach made a batting order is 3,268,800.
More about the permutation link is given below.
https://brainly.com/question/1216161
