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A beam of 7.96-MeV protons is incident on a target of _13^27 text(Al). Those that collide produce the reaction shown below.
p + 27 13 Al → 27 14 Si + n 27 14
Si has a mass of 26.986721 u. Neglecting any recoil of the product nucleus, determine the kinetic energy of the emerging neutrons. MeV

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Answer:

The kinetic energy = 2.35Mev

Explanation:

The standard value of the given mass of the elements are:

Mo= 1.007276U

Mn= 1.008665

M(Al)= 26.9815392u

We can now calculate Q

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