joychima73123
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an angle of elevation of the top of a church is 47 degree . if the tower is 31 meters above the ground how far from the tower is the point of the elevationwas taken . correct to 2 decimal place​

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ujalakhan18

Answer:

[tex]\boxed{Distance = 28.91 m}[/tex]

Step-by-step explanation:

Angle of elevation = α = 47 degrees

Height of the church = opposite = 31  m

Distance from point to the church = adjacent = x

So,

Tan α = [tex]\frac{opposite}{adjacent}[/tex]

Tan (47) = 31/x

=> 1.07 = 31/x

=> x = 31/1.07

=> x = 28.91 m (Upto 2 dps)

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