Answer:
(a) t = 7 sec approximately; (b) t = 6 sec
Step-by-step explanation:
(a) Â Set h(t)= -16(t-3)^2 + 288 = 0 and solve for t:
           16(t-3)^2 = 288 Â
    After simplification, this becomes (t - 3)^2 = 18, or t - 3 = ±3√2.
    Because t can be only zero or positive, t = 3 + 3√2 = 7 seconds
(b) Solve h(t)= -16(t-3)^2 + 288 = 150:
            -16(t-3)^2 = - 162
   or         (t - 3)^2 = 10.125, or
              t - 3 =  ±3.18, or, finally, t = 6.18 sec (discard t = -0.18 sec)