Answer:
The change in current at  [tex]R =456 \Omega[/tex] is  [tex]\frac{dI}{dt} = 7.032 * 10^{-5} A/s[/tex]
Explanation:
From the question we are told that
  The resistance is [tex]R = 465 \Omega[/tex]
   The current is  [tex]I = 0.09A[/tex]
  The change in voltage with respect to time is [tex]\frac{dV}{dt} = - 0.03 V/s[/tex]
   The change in resistance with time is  [tex]\frac{dR}{dt} = 0.03 \Omega /s[/tex]
According to ohm's law
    [tex]V = IR[/tex]
differentiating with respect to time using chain rule
       [tex]\frac{dV}{dt} = I \frac{dR}{dt} + R * \frac{dI}{dt}[/tex]
substituting value  at R = 456
       [tex]-0.0327 = 0.09 * 0.03 + 456* \frac{dI}{dt}[/tex]
       [tex]\frac{dI}{dt} = 7.032 * 10^{-5} A/s[/tex]
