A bag contains 2 red marbles, 2 green marbles, and 4 blue marbles. If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble wl be red and the second will be green

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Answer:

1/4

Step-by-step explanation:

There are 8 marbles 4 blue and the other half are red and green.

4 blue= 1/2

2 red= 1/4

2 green= 1/4

The red and the green both have a 1/4 chance.

Answer:

Answer

Step-by-step explanation:

There is a total of 8 marbles.

1. there are 2 red marbles in total so [tex]\frac{2}{8}[/tex] this can be simplify to [tex]\frac{1}{4}[/tex]

2. the probability of the second event is [tex]\frac{2}{7}[/tex]

for both event the probability will be

[tex]\frac{1}{4}[/tex]  ×  [tex]\frac{2}{7}[/tex] = [tex]\frac{1}{14}[/tex]