Let
x---------> Steve's time
y--------> Paul's time
we know that
[tex]x=10\ s\\y=12\ s[/tex]
[tex]x < y[/tex] ------> Steve is faster than Paul
Divide x by y
[tex]\frac{10}{12}=\frac{5}{6}[/tex]
therefore
the answer is the option
A. Steve is 5⁄6 as fast as Paul