
Answer:
Total number of birds = 1024+512+64= 1600
A. Frequency of GG birds = 1024/1600 = 0.64
B. Frequency of Gg birds = 512/1600 = 0.32
C. Frequency of gg birds = 64/1600 = 0.04
D. According to Hardy Weinberg equilibrium
G²+2Gg+g² = 1 or G+g = 1
G² = 0.64
G= √0.64 =0.8
g² = 0.04
g= √0.04 = 0.2
A chi square test will help to know if the population is in Hardy Weinberg equilibrium.
Expected   Observed    Expected   Deviation      d²    d²/E
ratio       value (O)     value (E)    , d= O-E
 Â
0.8 Â Â Â Â Â Â Â 1092 Â Â Â Â Â 960 Â Â Â Â Â +132 Â Â Â Â Â Â 17424 18.15 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0.2 Â Â Â Â Â Â Â 108 Â Â Â Â Â 240 Â Â Â Â Â Â Â Â Â -132 Â Â Â Â 17424 72.6
Chi square, X² = [tex]\sum d²/E[/tex] = 90.75
Degree of freedom = n- 1= 2 - 1 = 1
P value < 0.00001. So it's significant at C value of 0.05.
Therefore, this population doesn't obey Hardy Weinberg equilibrium.