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A 2.51 times 10^-2 L sample of a solution of Cu^ requires 3.30 times 10^-2 L of 0.132 M KMnO_4 solution to reach the equivalence point. The products of the reaction are Cu^2 and Mn^2 . What is the starting concentration of the Cu^ solution

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Answer:

0.868M Cuāŗ

Explanation:

The reaction is:

KMnOā‚„ + 5Cuāŗ + 8Hāŗ ā†’ 5CuĀ²āŗ + MnĀ²āŗ + Kāŗ + 4Hā‚‚O

Where 1 mol of KMnOā‚„ reacts with 5 moles of Cuāŗ

3.30x10ā»Ā²L of 0.132M KMnOā‚„ are:

3.30x10ā»Ā²L Ɨ Ā (0.132mol KMnOā‚„ / L) = 4.356x10ā»Ā³mol KMnOā‚„

As 1 mol reacts with 5 moles of Cuāŗ, moles of Cuāŗ are:

4.356x10ā»Ā³mol KMnOā‚„ Ɨ (5mol Cuāŗ / 1mol KMnOā‚„) = 0.02178moles Cuāŗ

As these moles are in 2.51x10ā»Ā²L, the starting concentration of the Cuāŗ solution is:

0.02178moles Cuāŗ / 2.51x10ā»Ā²L = 0.868M Cuāŗ

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