Answer:
Mass = 38.3 g
Explanation:
Given data:
Mass of Clâ‚‚ required = ?
Mass of phosphorus = 10.6 g
Solution:
Chemical equation:
P₄ + 6Cl₂  →  4PCl₃
Number of moles of Pâ‚„:
Number of moles = mass/ molar mass
Number of moles = 10.6 g/123.9 g/mol
Number of moles = 0.09 mol
Now we will compare the moles of Pâ‚„ with Clâ‚‚ from balance chemical equation.
        P₄       :       Cl₂
        1       :        6
       0.09     :       6×0.09 = 0.54 mol
Mass of chlorine gas:
Mass = number of moles × molar mass
Mass = 0.54 mol × 70.9 g/mol
Mass = 38.3 g