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A 6.2 kg block is pushed across a horizontal surface
with a horizontal force of 50.9 N against a friction
force of 13.7 N. What is the acceleration of the
block? Please report your answer with 1 number
behind the decimal and select the correct unit.
Answer:
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nkirotedoreen46

Answer:

6 m/s²

Explanation:

We are given;

  • The mass of the block as 6.2 kg
  • Horizontal force as 50.9 N
  • Frictional force as 13.7 N

We are required to determine the acceleration of the block.

  • According to second Newton's Law of motion; Resultant force is directly proportional to the rate of change in linear momentum.

Therefore;

F = Ma , where F is the resultant force, m is the mass and a is the acceleration.

In this case;

Resultant force, F = Horizontal force - friction force

                             = 50.9 N - 13.7 N

                             = 37.2 N

Thus;

37.2 N = 6.2 kg × a

Hence;

acceleration, a = 37.2 N ÷ 6.2 kg

                         = 6 m/s²

Therefore, the acceleration of the block is 6 m/s²

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