The reaction between potassium superoxide, KOâ‚‚, and COâ‚‚,
[tex]4KO_2+2CO_2 \rightarrow 2K_2CO_3+3O_2[/tex]
is used as a source of Oâ‚‚ and absorber of COâ‚‚ in self-contained breathing equipment used by rescue workers.
How many moles of Oâ‚‚ are produced when 0.300 mol of KOâ‚‚ reacts in this fashion?

Respuesta :

Answer:

  • 0.225 mol Oâ‚‚

Explanation:

1. Balanced chemcical reaction (given):

  • 4KOâ‚‚ + 2COâ‚‚ → 2Kâ‚‚CO₃ + 3Oâ‚‚

2. Mole ratio

Use the coefficients from the balanced chemical equation to form the mole ratio of Oâ‚‚ to KOâ‚‚:

         [tex]\dfrac{3molO_2}{4molKO_2}[/tex]

3. How many moles of Oâ‚‚ are produced when 0.300 mol of KOâ‚‚ reacts in this fashion?

Mutiply 0.300 mol of KOâ‚‚ by the mole ratio:

         [tex]0.300molKO_2\times 3molO_2/4molKO_2=0.225 molO_2[/tex]