
Respuesta :
Answer:
 v = 54.2 m / s
Explanation:
Let's use energy conservation for this problem.
Starting point Higher
     Em₀ = U = m g h
Final point. Lower
    [tex]Em_{f}[/tex] = K = ½ m v²
    Em₀ = Em_{f}
    m g h = ½ m v²
     v² = 2gh
     v = √ 2gh
Let's calculate
     v = √ (2 9.8 150)
     v = 54.2 m / s
The  speed will it be going when it gets to the ground is v = 54.2 m / s
Calculation of the speed:
Since strength of the gravitational field as g = 10 N/kg.A. If a hawk is slowly soaring at a height of about 150 meters
Now
m g h = ½ m v²
v² = 2gh
 v = √ 2gh
So,
v = √ (2 9.8 150)
v = 54.2 m / s
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