Answer:
The charge on the third object is ā 21.7nC
Explanation:
From Gauss's Law
Ī¦ = Q/Īµā
where;
Ī¦ is the total electric flux through the shell = ā 533 Nā mĀ²/C
Q is the total charge Q in the shell = ?
Īµā is the permittivity of free space = 8.85 x 10ā»Ā¹Ā²
From this equation; Ī¦ = Q/Īµā
Q = Ī¦ * Īµā = ā 533 * 8.85 x 10ā»Ā¹Ā²
Q = Ā ā4.7 X 10ā»ā¹ C = -4.7nC
Q = qā + qā + qā
ā 4.7nC = ā 14.0 nC + 31.0 nC + qā
ā 4.7nC ā 17nC = qā
ā 21.7nC = qā
Therefore, the charge on the third object is ā 21.7nC
