Answer:
Kc = 0.023
Explanation:
The detailed steps to determine the equilibrium constant in terms of concentration is as shown in the attachment.
Answer:
Kc = 0.0231
Explanation:
2Hâ‚‚Oâ‚‚(g) <-------> 2Hâ‚‚O(g) + Oâ‚‚(g)
Before the reaction,
Conc of Hâ‚‚Oâ‚‚ = 1.75/2.5 = 0.7M
Conc of Hâ‚‚O = 0M
Conc of Oâ‚‚ = 0M
At equilibrium
Conc of Hâ‚‚Oâ‚‚ remaining = 1.2/2.5 = 0.48M
Conc of Hâ‚‚0
We will obtain this from the stoichiometric balance
2 moles of Hâ‚‚Oâ‚‚ gives 2 moles of Hâ‚‚O
(1.75 - 1.2) moles of Hâ‚‚Oâ‚‚ had reacted at equilibrium and will give 0.55 moles of Hâ‚‚O
Conc of Hâ‚‚O at equilibrium = 0.55/2.5 = 0.22M
Conc of Oâ‚‚ at equilibrium = (0.55/2)/2.5 = 0.11M (the 0.55/2 is from the stoichiometric balance)
Kc = [H₂0]²[O₂]/[H₂O₂]²
Kc = [0.22]²[0.11]/[0.48]² = 0.0231 (L/mol) or (/M)
Hope this Helps!!!
