
Answer:
B. The perimeter of the given figure is 58 units.
Step-by-step explanation:
Here, the attachment is missing.
For the reference, i am attaching the correct figure specified in the question.
Now here let us assume the length of each card  = m units
The width of each card  = n units
Area of the given figure  = 180 sq units
Here, consider the given figure:
Here, the length of the rectangle  =  width of 4 cards
= 4 x ( Width of 1 card) Â = 4 x ( n) = Â 4 n
Also, Here, the length of the rectangle  =  width of 1 card + Length of 1 card
                                 = m + n
AREA OF THE RECTANGLE Â = LENGTH x WIDTH
⇒ 180  = 4 n ( m +  n)  .... (1)
Also, area of 1 card  = Length x width  = m x n  = mn
So, area of 9 such cards  = 9 x (m n) = 9  n m
AREA OF 9 RECTANGLES Â = AREA OF THE FIGURE
⇒  9  n m = 180  .... (2)
Â
Now, solving (1 ) and (2) fro values of m ,n we get:
Divide (1) by (2), Â and solve , we get: Â n = 5 units
Solving for m: 9 ( 5)  m = 180  , ⇒ m = 4 units
Now, the perimeter of figure  = Sum of all sides
= 2 ( Â m+ n) + 4n + Â 5m = 2(9) + 4(5) + 5(4) Â = 18 + 20 + Â 20 = 58
Hence the perimeter of the given figure is 58 units.