Answer:
Area: 16Ï€-32
Perimeter: 4Ï€ + 8sqrt(2)
Step-by-step explanation:
Area:
The shaded part plus the right triangle BCD makes a quarter circle, so you can find the area of the quarter circle minus the triangle.
For the quarter circle, the radius is 8, so the entire circle area is 64Ï€, making the quarter circle 16Ï€.
The triangle is 8*8/2 = 32.
So, the quarter circle minus the triangle, or the area, is 16Ï€-32.
Perimeter:
Again, this is a quarter circle. So, you can add the lengths of arc BD and the line segment BD.
The radius is 8, so the entire circumference is 16Ï€, making the quarter circle 4Ï€.
The hypotenuse of the right triangle will be sqrt(8*8+8*8), or 8sqrt(2).
Add and get 4Ï€ + 8sqrt(2) as your perimeter.