Which statement is correct?

A. The equation 3(3x-2)-4=5x has no solution
B. The equation 4(2x-3)-5=4x has exactly one solution
C. The equation 5(3x-2)-2=3x has exactly two solutions
D. The equation 6(2x-3)-3=2x has infinitely many solutions

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Respuesta :

Answer:

We can conclude that only option B is correct.

Step-by-step explanation:

A. The equation 3(3x - 2) - 4 = 5x has a solution.

Solving it we get,

3(3x - 2) - 4 = 5x

β‡’ 9x - 6 - 4 = 5x

β‡’ 4x = 10

β‡’ x = 2.5

B. The equation 4(2x - 3) - 5 = 4x has exactly one solution.

Solving it we get,

4(2x - 3) - 5 = 4x

β‡’ 8x - 12 - 5 = 4x

β‡’ 4x = 17

β‡’ x = 4.25

C. The equation 5(3x - 2) - 2 = 3x also has exactly one solution.

Solving it we get,

5(3x - 2) - 2 = 3x

β‡’ 15x - 10 - 2 = 3x

β‡’ 12x = 12

β‡’ x = 1

D. The equation 6(2x - 3) - 3 = 2x also has exactly one solution.

Solving it we get,

6(2x - 3) - 3 = 2x

β‡’ 12x - 18 - 3 = 2x

β‡’ 10x = 21

β‡’ x = 2.1

Therefore, we can conclude that only option B is correct. (Answer)