
Answer: 8400 J
Explanation:
The formula referenced in the question is:
[tex]Q=m. c. \Delta T[/tex] Â
Where:
[tex]Q[/tex] Â is the thermal energy
[tex]m=100g \frac{1 kg}{1000 g}=0.1 kg[/tex] is the mass  of the water sample
[tex]c=4200 \frac{J}{kg\°C}[/tex]  is the specific heat capacity of  water
[tex]\Delta T=20\°C[/tex]  is the variation in temperature
Solving:
[tex]Q=(0.1 kg)(4200 \frac{J}{kg\°C})(20\°C)[/tex] Â
[tex]Q=8400 J[/tex] Â This is the thermal energy released