Answer:
Molarity = 0.61 M.
Explanation:
atomic mass of AgNO3 = 108 + 14 + 3×16 = 170 g.
therefore number of moles in 34.9 g of AgNO3 = [tex]\frac{34.9}{170}[/tex]
molarity = (number of moles of solute)/(volume of solution in Litre)
= [tex]\frac{34.9\times 1000}{170\times 337}[/tex] = 0.61 M
