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A proton and an electron are released from rest in the center of a capacitor.

A) Is the force ratio Fp/Fe greater than 1, less than 1, or equal to 1?

B) Is the acceleration ratio ap/ae greater than 1, less than 1, or equal to 1?

Relax

Respuesta :

Answer:

a)  equal 1, b) less than 1

Explanation:

a) the electric force is given by

         Fe = q E

The charge of the electron and proton has the same value, that of the proton is positive and that of the electron is negative

Proton

        Fp = qE

Electron

         Fe = - q E

         Fp / Fe = -1

If we do not take into account the sign the relationship is equal to one (1)

b) to calculate the force we use Newton's second law

           F = ma

           qE = m a

           a = q E / m

The mass of the proton much greater than the mass of the electron

          ap = q E / [tex]m_{p}[/tex]

          ae = - q E /  [tex]m_{e}[/tex]

          ap / ae =  [tex]m_{e}[/tex] /  [tex]m_{p}[/tex] =  [tex]m_{e}[/tex]/1600  [tex]m_{e}[/tex] =1/1600

 It is much smaller than 1

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