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4. Ammonium nitrate (NH4NO3) fertilizer decomposes explosively into gaseous nitrogen, oxygen, and water, resulting in huge thermal energy produces hot and damaging gases. How much nitrogen can we introduce in our garden when 800 grams of ammonium nitrate (NH4NO3)

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dsdrajlin

Answer:

280 g

Explanation:

Let's consider the decomposition of ammonium nitrate.

NH₄NO₃(s) ⇒ N₂(g) + 0.5 O₂(g) + 2 H₂O(g)

We can establish the following relations:

  • The molar mass of NHâ‚„NO₃ is 80.04 g/mol.
  • The molar ratio of NHâ‚„NO₃ to Nâ‚‚ is 1:1.
  • The molar mass of Nâ‚‚ is 28.01 g/mol.

The mass of N₂ produced when 800 g of NH₄NO₃ react is:

[tex]800gNH_{4}NO_{3}.\frac{1molNH_{4}NO_{3}}{80.04gNH_{4}NO_{3}} .\frac{1molN_{2}}{1molNH_{4}NO_{3}} .\frac{28.01gN_{2}}{1molN_{2}} =280gN_{2}[/tex]