sic16
sic16
13-06-2016
Mathematics
contestada
Find the exact values of cos 0 and sin 0 for -120
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nobillionaireNobley
nobillionaireNobley
15-06-2016
[tex]sin (-120) = sin(180-60)=sin60= \frac{ \sqrt{3} }{2} \\ cos(-120)=-cos(180-60)=-cos60=- \frac{1}{2} [/tex]
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