In thinking of an inductor as a circuit element, it is helpful to consider its limiting behavior at high and low frequencies. At one extreme, the inductor might behave like a short circuit, that is, like a resistor with almost no resistance (an ideal wire) having essentially no voltage drop across it no matter what the current. Alternatively, the inductor might behave like an open circuit, that is, like a resistor with large resistance so that essentially no current will flow no matter what the applied voltage. Based on the formula you obtained for the reactance, how does an inductor behave at high and low frequencies?
A) like a short circuit at both high frequencies and low frequenciesB) like an open circuit at both high frequencies and low frequenciesC) like an open circuit at high frequencies and a short circuit at low frequenciesD) like an open circuit at low frequencies and a short circuit at high frequencies

The impedance produce by the presence of an inductance in an electric circuit has a general equation Z(r) = jωl where j is the imaginay number, l is the inductor in henrios and ω is the frecuency of the curent ( ω = 2πf , f is the frecuency in hertz)

So module of the inductance directly depends on ω = 2πf then when f the frecuency increase, the value of ωl, also increase and when the value of f decrease ωl will decrease. For very high value of ω the inductance can become very very high ( even up to an open circuit ) and the opposite for very low values of frecuencies ωl could be very low (as to a short circuit