
Answer:
Multiply the second equation by β2 to get β8x β 6y = β30.
Step-by-step explanation:
{2x + 6y = 12
{4x + 3y = 15
{2x + 6y = 12
{β8x β 6y = β30 >> New Equation
* Doing this will give you additive inverses of β6y and 6y, which result in 0, so they are both ELIMINATED.
** [3, 1] is your solution.
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