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Write the slope-intercept form of the given line. Include your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution.

PLEASE HELP WILL GIVE BRAINLIESTWrite the slopeintercept form of the given line Include your work in your final answer Type your answer in the box provided or u class=
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frika

Answer:

[tex]y=-\dfrac{1}{3}x+1[/tex]

Step-by-step explanation:

Given line intersects the x-axis at point (3,0) and the y-axis at point (0,1).

The equation of this line is

[tex]\dfrac{x-3}{0-3}=\dfrac{y-0}{1-0}\\ \\\dfrac{x-3}{-3}=\dfrac{y}{1}\\ \\x-3=-3y\\ \\y=-\dfrac{1}{3}x+1[/tex]

The equation in the slope-intercept form is

[tex]y=-\dfrac{1}{3}x+1[/tex]

noobxvibes

Answer:

1) The line is passing through the y-axis at -3.

    Now to find the slope, use . We'll use the points ⇒ (-2, 0), (0, -3).

     =  

    The slope of the line is .

     

     Plug in what we know into y = mx + b.

     m is the slope and b is the y-intercept.

     

     y = -3/2x - 3 is the slope-intercept form for #1.

2) The line is passing through the y-axis at -1.

    Use the same slope formula, . We'll use the points ⇒ (1, 0), (0, -1).

     =  

    The slope of the line is 1.

    Plug the numbers in to y = mx + b.

     

    y = x - 1 is the slope-intercept form for #2.

Step-by-step explanation: