
Answer
a)  y   |    p(y)
  25  |    0.8
  100  |   0.15
  300  |    0.05
E(y) = ∑ y . p(y)
E(y) = 25 × 0.8 + 100 × 0.15 + 300 × 0.05
E(y) = 50
average class size equal to E(y) = 50
b)  y   |    p(y)
  25  |   [tex]\dfrac{16\times 25}{1000}=0.4[/tex]
  100  |   [tex]\dfrac{3\times 100}{1000}=0.3[/tex]
  300  |    [tex]\dfrac{1\times 300}{1000}=0.3[/tex]
E(y) = ∑ y . p(y)
E(y) = 25 × 0.4 + 100 × 0.3 + 300 × 0.3
E(y) = 130
average class size equal to E(y) = 130
c) Average Student in the class in a school = 50
 Average student at the school has student = 130