
Answer:
B = 0.10 M of AlClâ
Explanation:
A = 0.10 M NaCl
NaCl â Naâș + Clâ»
sodium chloride dissociate into sodium and chlorine ions. The one mole of NaCl produced on mole of Naâș and one mole of Clâ», so concentration of chloride ions will be 0.10 M.
B = 0.10 M of AlClâ
AlClâ Â â Â Â AlÂłâș + 3Clâ»
AlClâ dissociate into aluminium cation and chlorine anion. one mole of AlClâ dissociate into one mole of AlÂłâș and three mole of Clâ».
so concentration of chloride ion in 0.10 M solution is
0.10 Ă 3 = 0.3 M
C = 0.10 M MgClâ
MgClâ Â â MgÂČâș + Â 2Clâ»
MgClâ dissociate into one mole of MgÂČâș and two mole of Clâ».
so concentration of chloride ions in 0.10 M solution of MgClâ is,
2Ă 0.10 M = 0.20 M
d = 0.05 M CaClâ Â
CaClâ Â â Â CaÂČâș + Â 2Clâ»
CaClâ dissociate into one mole of  CaÂČâș and two mole of Clâ», So concentration of chloride ions in 0.05 M CaClâ is
2Ă 0.05 = 0.1 M