Answer:
0.971 grams
Explanation:
Given:
Temperature = 3.0° C = 3 + 273 = 276 K
Volume, V = 5.0 L
Pressure, P = 0.100 atm
Now, from the relation
PV = nRT
where,
n is the number of moles,
R is the ideal gas constant  = 0.082057 L atm/mol.K
thus,
0.1 Ă— 5 = n Ă— Â 0.082057 Ă— 276
or
n = 0.022 moles
Also,
Molar mass of the Dinitrogen monoxide gas (Nâ‚‚O)
= 2 Ă— Molar mass of nitrogen + 1 Ă— Molar mass of oxygen
= 2 Ă— 14 + 16 = 44 grams/mol
Therefore, Mass of 0.022 moles of Nâ‚‚O = 0.022 Ă— 44 = 0.971 grams