Answer the following and round to the correct number of significant figures (don't forget units).

a) 0.02123 m + 1.12 m + 0.00123 m =

b) 2.3 cm - 1.23 cm + 120 cm =

c) 25,430 km - 3,500 km + 200 km =

d) (1.21 x 105 ) x (2.6 x 103 ) =

e) 7.13 mm x 9.1 mm =

f) 3.0 cm x 8.222 cm =

g) 4.1 g ÷ 0.121 cm =

h) 0.413 ÷ (9.212 x 103 ) =

i) (12.1 cm - 4.15 cm) / 35.64 g =

j) (11.00 m - 3.356 m) x 45.1 kg /35.64 s =

k) 73.0 x 1.340 x (25.31 – 1.6) =

l) (418.7 x 31.8) / (19.27 – 18.98) =

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rk9506863 rk9506863 · Answer 1 · 2019-09-18T13:59:02+02:00

Answer:

a) 0.02123 m + 1.12 m + 0.00123 m = 1.14246m it can be round off as 1.1425m

b) 2.3 cm - 1.23 cm + 120 cm = 121.07 cm it can be round off as 121.1 cm

c) 25,430 km - 3,500 km + 200 km = 22130 km

d) (1.21 x 105 ) x (2.6 x 103 ) = 34023.99 it can be round off as 34024

e) 7.13 mm x 9.1 mm = 64.883 mm it can be round off as 65 mm

f) 3.0 cm x 8.222 cm = 24.666 cm it can be round off as 25 cm

g) 4.1 g ÷ 0.121 cm = 33.8842 g/cm it can round off as 34 g/cm

h) 0.413 ÷ (9.212 x 103 ) = 0.00043527

i) (12.1 cm - 4.15 cm) / 35.64 g = 0.223063973 cm/g

j) (11.00 m - 3.356 m) x 45.1 kg /35.64 s = 9.672962963 m kg/s

k) 73.0 x 1.340 x (25.31 – 1.6) = 2319.3122

l) (418.7 x 31.8) / (19.27 – 18.98) = 45912.62069 45912.6207