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A jet lands with a speed of 100 m/s and can accelerate uniformly at a rate of -5.0 m/s^2 as it comes to rest. What is the minimum length runway to land this plane? A. 1000 m
B. 20 m
C. 675 m
D. 500 m

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Respuesta :

Answer:

A ) 1000 m.

Explanation:

Here initial velocity u = 100 m /s

Final velocity v = 0

Acceleration a = -5 ms⁻²

Distance travelled = S

v² = u² + 2aS

0 = (100)² -2 x 5 S

S = 10000/ 10

=1000 m.

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