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A small pad subjected to a shearing force is deformed at the top of the pad 0.12 in. The heigfit of the pad is 1.15 in. What is the shearing strain (rad) on the pad?

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Answer:

Shearing strain will be 0.1039 radian

Explanation:

We have given change in length [tex]\Delta L=0.12inch[/tex]

Length of the pad L = 1.15 inch

We have to find the shearing strain

Shearing strain is given by

[tex]\alpha =tan^{-1}\frac{\Delta L}{L}=tan^{-1}\frac{0.12}{1.15}=5.9571^{\circ}[/tex]

Shearing strain is always in radian so we have to change angle in radian

So [tex]5.9571\times \frac{\pi }{180}=0.1039radian[/tex]

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