A group of naturalists catch, tag and release 121 trout into a lake. The next day they catch and release 48 trout, of which 22 had been tagged. Using this ratio, how many trout would be estimated to be in the lake?

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Answer:

264.

Step-by-step explanation:

Let x represent the number of trout in the lake.

We have been given that a group of naturalists catch, tag and release 121 trout into a lake. The next day they catch and release 48 trout, of which 22 had been tagged.

Using proportions, we will get:

[tex]\frac{\text{Total trouts}}{\text{Tagged trouts}}=\frac{48}{22}[/tex]

[tex]\frac{x}{121}=\frac{48}{22}[/tex]

[tex]\frac{x}{121}*121=\frac{48}{22}*121[/tex]

[tex]x=\frac{24}{11}*121[/tex]

[tex]x=24*11[/tex]

[tex]x=264[/tex]

Therefore, there would be approximately 264 trout in the lake.

264 trouts are estimated to be in the lake.

Using proportion, we write: Tagged trout/Total Trout

This becomes 22/48.

In order to use cross multiplication, we write another fraction using x, the total number of trout in the lake: 121/x.

Now we have 121/x=22/48.

We cross multiply.

121*48=22x.

(121*48)/22 becomes:

264.