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Sodium hydroxide is used extensively in acid-base titrations because it is a strong, inexpensive base. A sodium hydroxide solution was standardized by titrating 38.87 mL of 0.1994 M standard hydrochloric acid. The initial buret reading of the sodium hydroxide was 1.16 mL, and the final reading was 36.18 mL. What was the molarity of the base solution?

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Respuesta :

Answer: The molarity of the base solution is 0.22 M.

Explanation:

According to the neutralization law,

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of [tex]HCl[/tex] solution = 0.1994 M

[tex]V_1[/tex] = volume of [tex]HCl[/tex] solution = 38.87 ml

[tex]M_2[/tex] = molarity of [tex]NaOH[/tex] solution = ?

[tex]V_2[/tex] = volume of [tex]NaOH[/tex] solution = Final reading - Initial reading = 36.18 - 1.16 = 35.02 ml

[tex]n_1[/tex] = valency of [tex]HCl[/tex] = 1

[tex]n_2[/tex] = valency of [tex]NaOH[/tex] = 1

[tex]1\times 0.1994\times 38.87=1\times M_2\times 35.02[/tex]

[tex]M_2=0.22M[/tex]

Therefore, the molarity of the base solution is 0.22 M.

Answer:

0.221M

Explanation:

applying molarity equation

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