
Answer:
Step-by-step explanation:
Given that
Group  Group One   Group Two Â
Mean    26.00 23.00
SD Â Â Â Â Â Â Â Â 2.00 4.00
SEM Â Â Â Â 0.40 1.21
N Â Â Â Â Â Â Â Â Â Â 25 Â Â 11 Â Â
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34 Â
 standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)