Vividerla
Vividerla Vividerla
  • 12-08-2019
  • Mathematics
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Please help! 1 question! 50 points! Show your work!

Please help 1 question 50 points Show your work class=
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sqdancefan
sqdancefan sqdancefan
  • 15-08-2019

Answer:

  [tex]\dfrac{2x}{3a^2}[/tex]

Step-by-step explanation:

[tex]\dfrac{3a^4b}{2x}\cdot\dfrac{4x^2}{9a^6b}=\dfrac{3\cdot 4}{2\cdot 9}a^{4-6}b^{1-1}x^{2-1}=\dfrac{2x}{3a^2}[/tex]

The applicable rules of exponents are ...

  • (a^b)(a^c) = a^(b+c)
  • a^-b = 1/a^b
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