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A 4.5 liter sample of a gas at 2 atm and 300 K has 0.80 mole of gas. If 0.35 mole of the gas is added to the sample at the same temperature and pressure, what is the volume of the gas?

3.9 liters
5.3 liters
6.3 liters
6.5 litersā€‹

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Respuesta :

superman1987

Answer:

6.5 litersā€‹.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R Ā is the general gas constant,

T is the temperature of the gas in K.

  • If P and T are constant, and have different values of n and V:

(Vā‚nā‚‚) = (Vā‚‚nā‚)

  • Knowing that:

Vā‚ Ā = 4.5 L, nā‚ = 0.80 mol,

Vā‚‚ Ā = Ā ??? L, nā‚‚ = 0.35 + 0.80 = 1.15 mol.

  • Applying in the above equation

(Vā‚nā‚‚) = (Vā‚‚nā‚)

āˆ“ Vā‚‚ = (Vā‚nā‚‚)/nā‚ = (4.5 L)(1.15 mol)/(0.8 mol) = 6.469 L ā‰… 6.5 L.

So, the right choice is: 6.5 litersā€‹.

Answer 6.5 liters

Explanation:

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