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A stone is thrown vertically downwards from the top of a skyscraper with an initial speed of 5.10m/s. The stone hits the street below 7.60 seconds after being thrown.How tall is the skyscraper?

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MathPhys

Answer:

322 m

Explanation:

y = y₀ + v₀ t + ½ gt²

If we take down to be positive, then:

y = 0 + (5.10) (7.60) + ½ (9.8) (7.60)²

y = 322 m

The skyscraper is 322 m tall.

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